Solve 2(m^2+1^2)-(2m^2-1^2)

$$2( { m }^{ 2 } + { 1 }^{ 2 } )-(2 { m }^{ 2 } - { 1 }^{ 2 } )$$

Evaluate

$$3$$

Solution Steps

Calculate 1 to the power of 2 and get 1.

$$2\left(m^{2}+1\right)-\left(2m^{2}-1^{2}\right)$$

Use the distributive property to multiply 2 by m^{2}+1.

$$2m^{2}+2-\left(2m^{2}-1^{2}\right)$$

Calculate 1 to the power of 2 and get 1.

$$2m^{2}+2-\left(2m^{2}-1\right)$$

To find the opposite of 2m^{2}-1, find the opposite of each term.

$$2m^{2}+2-2m^{2}+1$$

Combine 2m^{2} and -2m^{2} to get 0.

$$2+1$$

Add 2 and 1 to get 3.

$$3$$

Factor

$$3$$