Solve 2(1/3)-8+1/3=2(1/3)-6-5(1/3)

$$2( \frac{ 1 }{ 3 } )-8+ \frac{ 1 }{ 3 } =2( \frac{ 1 }{ 3 } )-6-5( \frac{ 1 }{ 3 } )$$

Verify

Solution Steps

Multiply 2 and \frac{1}{3} to get \frac{2}{3}.

$$\frac{2}{3}-8+\frac{1}{3}=2\times \frac{1}{3}-6-5\times \frac{1}{3}$$

Convert 8 to fraction \frac{24}{3}.

$$\frac{2}{3}-\frac{24}{3}+\frac{1}{3}=2\times \frac{1}{3}-6-5\times \frac{1}{3}$$

Since \frac{2}{3} and \frac{24}{3} have the same denominator, subtract them by subtracting their numerators.

$$\frac{2-24}{3}+\frac{1}{3}=2\times \frac{1}{3}-6-5\times \frac{1}{3}$$

Subtract 24 from 2 to get -22.

$$-\frac{22}{3}+\frac{1}{3}=2\times \frac{1}{3}-6-5\times \frac{1}{3}$$

Since -\frac{22}{3} and \frac{1}{3} have the same denominator, add them by adding their numerators.

$$\frac{-22+1}{3}=2\times \frac{1}{3}-6-5\times \frac{1}{3}$$

Add -22 and 1 to get -21.

$$\frac{-21}{3}=2\times \frac{1}{3}-6-5\times \frac{1}{3}$$

Divide -21 by 3 to get -7.

$$-7=2\times \frac{1}{3}-6-5\times \frac{1}{3}$$

Multiply 2 and \frac{1}{3} to get \frac{2}{3}.

$$-7=\frac{2}{3}-6-5\times \frac{1}{3}$$

Convert 6 to fraction \frac{18}{3}.

$$-7=\frac{2}{3}-\frac{18}{3}-5\times \frac{1}{3}$$

Since \frac{2}{3} and \frac{18}{3} have the same denominator, subtract them by subtracting their numerators.

$$-7=\frac{2-18}{3}-5\times \frac{1}{3}$$

Subtract 18 from 2 to get -16.

$$-7=-\frac{16}{3}-5\times \frac{1}{3}$$

Multiply 5 and \frac{1}{3} to get \frac{5}{3}.

$$-7=-\frac{16}{3}-\frac{5}{3}$$

Since -\frac{16}{3} and \frac{5}{3} have the same denominator, subtract them by subtracting their numerators.

$$-7=\frac{-16-5}{3}$$

Subtract 5 from -16 to get -21.

$$-7=\frac{-21}{3}$$

Divide -21 by 3 to get -7.

$$-7=-7$$

Compare -7 and -7.

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