Solve 2+5+3+3+2+3+4+3div2

$$2+5+3+3+2+3+4+3 \div 2$$

Evaluate

$$\frac{47}{2}=23.5$$

Solution Steps

Add 2 and 5 to get 7.

$$7+3+3+2+3+4+\frac{3}{2}$$

Add 7 and 3 to get 10.

$$10+3+2+3+4+\frac{3}{2}$$

Add 10 and 3 to get 13.

$$13+2+3+4+\frac{3}{2}$$

Add 13 and 2 to get 15.

$$15+3+4+\frac{3}{2}$$

Add 15 and 3 to get 18.

$$18+4+\frac{3}{2}$$

Add 18 and 4 to get 22.

$$22+\frac{3}{2}$$

Convert 22 to fraction \frac{44}{2}.

$$\frac{44}{2}+\frac{3}{2}$$

Since \frac{44}{2} and \frac{3}{2} have the same denominator, add them by adding their numerators.

$$\frac{44+3}{2}$$

Add 44 and 3 to get 47.

$$\frac{47}{2}$$

Factor

$$\frac{47}{2} = 23\frac{1}{2} = 23.5$$