Solve for y_1
y_{1}=\frac{\sin(x)}{2}
Solve for x
x=-\arcsin(2y_{1})+2\pi n_{1}+\pi \text{, }n_{1}\in \mathrm{Z}
x=\arcsin(2y_{1})+2\pi n_{2}\text{, }n_{2}\in \mathrm{Z}\text{, }|y_{1}|\leq \frac{1}{2}
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2y_{1}=\sin(x)
The equation is in standard form.
\frac{2y_{1}}{2}=\frac{\sin(x)}{2}
Divide both sides by 2.
y_{1}=\frac{\sin(x)}{2}
Dividing by 2 undoes the multiplication by 2.
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