Solve for x
x=\frac{2\left(y+4\right)}{3}
Solve for y
y=\frac{3x}{2}-4
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-3x=-8-2y
Subtract 2y from both sides.
-3x=-2y-8
The equation is in standard form.
\frac{-3x}{-3}=\frac{-2y-8}{-3}
Divide both sides by -3.
x=\frac{-2y-8}{-3}
Dividing by -3 undoes the multiplication by -3.
x=\frac{2y+8}{3}
Divide -8-2y by -3.
2y=-8+3x
Add 3x to both sides.
2y=3x-8
The equation is in standard form.
\frac{2y}{2}=\frac{3x-8}{2}
Divide both sides by 2.
y=\frac{3x-8}{2}
Dividing by 2 undoes the multiplication by 2.
y=\frac{3x}{2}-4
Divide -8+3x by 2.
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