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y^{3}\left(2y-1\right)+2\left(2y-1\right)
Do the grouping 2y^{4}-y^{3}+4y-2=\left(2y^{4}-y^{3}\right)+\left(4y-2\right), and factor out y^{3} in the first and 2 in the second group.
\left(2y-1\right)\left(y^{3}+2\right)
Factor out common term 2y-1 by using distributive property. Polynomial y^{3}+2 is not factored since it does not have any rational roots.