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2y^{2}-17y-y^{4}=0
Subtract y^{4} from both sides.
-t^{2}+2t-17=0
Substitute t for y^{2}.
t=\frac{-2±\sqrt{2^{2}-4\left(-1\right)\left(-17\right)}}{-2}
All equations of the form ax^{2}+bx+c=0 can be solved using the quadratic formula: \frac{-b±\sqrt{b^{2}-4ac}}{2a}. Substitute -1 for a, 2 for b, and -17 for c in the quadratic formula.
t=\frac{-2±\sqrt{-64}}{-2}
Do the calculations.
t\in \emptyset
Since the square root of a negative number is not defined in the real field, there are no solutions.
y\in \emptyset
Since t=y^{2}, the original equation does not have any solutions.