Solve for x
x=\frac{-2y-2}{3}
Solve for y
y=-\frac{3x}{2}-1
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-3x-2=2y
Swap sides so that all variable terms are on the left hand side.
-3x=2y+2
Add 2 to both sides.
\frac{-3x}{-3}=\frac{2y+2}{-3}
Divide both sides by -3.
x=\frac{2y+2}{-3}
Dividing by -3 undoes the multiplication by -3.
x=\frac{-2y-2}{3}
Divide 2+2y by -3.
2y=-3x-2
The equation is in standard form.
\frac{2y}{2}=\frac{-3x-2}{2}
Divide both sides by 2.
y=\frac{-3x-2}{2}
Dividing by 2 undoes the multiplication by 2.
y=-\frac{3x}{2}-1
Divide -3x-2 by 2.
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