Solve for x
x=\frac{8-2y}{5}
Solve for y
y=-\frac{5x}{2}+4
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5x-8=-2y
Subtract 2y from both sides. Anything subtracted from zero gives its negation.
5x=-2y+8
Add 8 to both sides.
5x=8-2y
The equation is in standard form.
\frac{5x}{5}=\frac{8-2y}{5}
Divide both sides by 5.
x=\frac{8-2y}{5}
Dividing by 5 undoes the multiplication by 5.
2y-8=-5x
Subtract 5x from both sides. Anything subtracted from zero gives its negation.
2y=-5x+8
Add 8 to both sides.
2y=8-5x
The equation is in standard form.
\frac{2y}{2}=\frac{8-5x}{2}
Divide both sides by 2.
y=\frac{8-5x}{2}
Dividing by 2 undoes the multiplication by 2.
y=-\frac{5x}{2}+4
Divide -5x+8 by 2.
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