Solve for y
y=-\frac{3z}{2}+1
Solve for z
z=\frac{2-2y}{3}
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2y=2-3z
Subtract 3z from both sides.
\frac{2y}{2}=\frac{2-3z}{2}
Divide both sides by 2.
y=\frac{2-3z}{2}
Dividing by 2 undoes the multiplication by 2.
y=-\frac{3z}{2}+1
Divide 2-3z by 2.
3z=2-2y
Subtract 2y from both sides.
\frac{3z}{3}=\frac{2-2y}{3}
Divide both sides by 3.
z=\frac{2-2y}{3}
Dividing by 3 undoes the multiplication by 3.
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\frac { d } { d x } \frac { ( 3 x ^ { 2 } - 2 ) } { ( x - 5 ) }
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Limits
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