Solve 2y+3x-3=10

$$2 y + 3 x - 3 = 10$$

Solve for x

$$x=\frac{13-2y}{3}$$

Steps for Solving Linear Equation

Subtract 2y from both sides.

$$3x-3=10-2y$$

Add 3 to both sides.

$$3x=10-2y+3$$

Add 10 and 3 to get 13.

$$3x=13-2y$$

Divide both sides by 3.

$$\frac{3x}{3}=\frac{13-2y}{3}$$

Dividing by 3 undoes the multiplication by 3.

$$x=\frac{13-2y}{3}$$

Solve for y

$$y=\frac{13-3x}{2}$$

Steps for Solving Linear Equation

Subtract 3x from both sides.

$$2y-3=10-3x$$

Add 3 to both sides.

$$2y=10-3x+3$$

Add 10 and 3 to get 13.

$$2y=13-3x$$

Divide both sides by 2.

$$\frac{2y}{2}=\frac{13-3x}{2}$$

Dividing by 2 undoes the multiplication by 2.

$$y=\frac{13-3x}{2}$$