Solve for x
x=\frac{-2y-8}{3}
Solve for y
y=-\frac{3x}{2}-4
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3x=-8-2y
Subtract 2y from both sides.
3x=-2y-8
The equation is in standard form.
\frac{3x}{3}=\frac{-2y-8}{3}
Divide both sides by 3.
x=\frac{-2y-8}{3}
Dividing by 3 undoes the multiplication by 3.
2y=-8-3x
Subtract 3x from both sides.
2y=-3x-8
The equation is in standard form.
\frac{2y}{2}=\frac{-3x-8}{2}
Divide both sides by 2.
y=\frac{-3x-8}{2}
Dividing by 2 undoes the multiplication by 2.
y=-\frac{3x}{2}-4
Divide -8-3x by 2.
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