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Solve for x
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2xy=-3+2y^{2}
Add 2y^{2} to both sides.
2yx=2y^{2}-3
The equation is in standard form.
\frac{2yx}{2y}=\frac{2y^{2}-3}{2y}
Divide both sides by 2y.
x=\frac{2y^{2}-3}{2y}
Dividing by 2y undoes the multiplication by 2y.
x=y-\frac{3}{2y}
Divide -3+2y^{2} by 2y.