Solve 2xy+6xz=2

$$2 x y + 6 x z = 2$$

Solve for x

$$x=\frac{1}{y+3z}$$

$$y\neq -3z$$

Steps for Solving Linear Equation

Combine all terms containing x.

$$\left(2y+6z\right)x=2$$

Divide both sides by 2y+6z.

$$\frac{\left(2y+6z\right)x}{2y+6z}=\frac{2}{2y+6z}$$

Dividing by 2y+6z undoes the multiplication by 2y+6z.

$$x=\frac{2}{2y+6z}$$

Divide 2 by 2y+6z.

$$x=\frac{1}{y+3z}$$

Solve for y

$$y=-3z+\frac{1}{x}$$

$$x\neq 0$$

Steps for Solving Linear Equation

Subtract 6xz from both sides.

$$2xy=2-6xz$$

Divide both sides by 2x.

$$\frac{2xy}{2x}=\frac{2-6xz}{2x}$$

Dividing by 2x undoes the multiplication by 2x.

$$y=\frac{2-6xz}{2x}$$

Divide 2-6xz by 2x.

$$y=-3z+\frac{1}{x}$$