Solve 2xu+2x=3

$$2 x u + 2 x = 3$$

Solve for u

$$u=-1+\frac{3}{2x}$$

$$x\neq 0$$

Steps for Solving Linear Equation

Subtract 2x from both sides.

$$2xu=3-2x$$

Divide both sides by 2x.

$$\frac{2xu}{2x}=\frac{3-2x}{2x}$$

Dividing by 2x undoes the multiplication by 2x.

$$u=\frac{3-2x}{2x}$$

Divide 3-2x by 2x.

$$u=-1+\frac{3}{2x}$$

Solve for x

$$x=\frac{3}{2\left(u+1\right)}$$

$$u\neq -1$$

Steps for Solving Linear Equation

Combine all terms containing x.

$$\left(2u+2\right)x=3$$

Divide both sides by 2u+2.

$$\frac{\left(2u+2\right)x}{2u+2}=\frac{3}{2u+2}$$

Dividing by 2u+2 undoes the multiplication by 2u+2.

$$x=\frac{3}{2u+2}$$

Divide 3 by 2u+2.

$$x=\frac{3}{2\left(u+1\right)}$$