Solve for m
m=-2+\frac{5}{2x}
x\neq 0
Solve for x
x=\frac{5}{2\left(m+2\right)}
m\neq -2
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2xm=5-4x
Subtract 4x from both sides.
\frac{2xm}{2x}=\frac{5-4x}{2x}
Divide both sides by 2x.
m=\frac{5-4x}{2x}
Dividing by 2x undoes the multiplication by 2x.
m=-2+\frac{5}{2x}
Divide 5-4x by 2x.
\left(2m+4\right)x=5
Combine all terms containing x.
\frac{\left(2m+4\right)x}{2m+4}=\frac{5}{2m+4}
Divide both sides by 2m+4.
x=\frac{5}{2m+4}
Dividing by 2m+4 undoes the multiplication by 2m+4.
x=\frac{5}{2\left(m+2\right)}
Divide 5 by 2m+4.
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