Solve for x
x=\frac{y-2z+7}{2}
Solve for y
y=2x+2z-7
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2x+2z=7+y
Add y to both sides.
2x=7+y-2z
Subtract 2z from both sides.
2x=y-2z+7
The equation is in standard form.
\frac{2x}{2}=\frac{y-2z+7}{2}
Divide both sides by 2.
x=\frac{y-2z+7}{2}
Dividing by 2 undoes the multiplication by 2.
x=\frac{y}{2}-z+\frac{7}{2}
Divide 7+y-2z by 2.
-y+2z=7-2x
Subtract 2x from both sides.
-y=7-2x-2z
Subtract 2z from both sides.
-y=7-2z-2x
The equation is in standard form.
\frac{-y}{-1}=\frac{7-2z-2x}{-1}
Divide both sides by -1.
y=\frac{7-2z-2x}{-1}
Dividing by -1 undoes the multiplication by -1.
y=2x+2z-7
Divide 7-2x-2z by -1.
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Limits
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