Solve for x
x\geq \frac{3}{4}
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2x-12+14x\geq 0
Add 14x to both sides.
16x-12\geq 0
Combine 2x and 14x to get 16x.
16x\geq 12
Add 12 to both sides. Anything plus zero gives itself.
x\geq \frac{12}{16}
Divide both sides by 16. Since 16 is positive, the inequality direction remains the same.
x\geq \frac{3}{4}
Reduce the fraction \frac{12}{16} to lowest terms by extracting and canceling out 4.
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Limits
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