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2x-x^{2}+7x-8=0
To find the opposite of x^{2}-7x, find the opposite of each term.
9x-x^{2}-8=0
Combine 2x and 7x to get 9x.
-x^{2}+9x-8=0
Rearrange the polynomial to put it in standard form. Place the terms in order from highest to lowest power.
a+b=9 ab=-\left(-8\right)=8
To solve the equation, factor the left hand side by grouping. First, left hand side needs to be rewritten as -x^{2}+ax+bx-8. To find a and b, set up a system to be solved.
1,8 2,4
Since ab is positive, a and b have the same sign. Since a+b is positive, a and b are both positive. List all such integer pairs that give product 8.
1+8=9 2+4=6
Calculate the sum for each pair.
a=8 b=1
The solution is the pair that gives sum 9.
\left(-x^{2}+8x\right)+\left(x-8\right)
Rewrite -x^{2}+9x-8 as \left(-x^{2}+8x\right)+\left(x-8\right).
-x\left(x-8\right)+x-8
Factor out -x in -x^{2}+8x.
\left(x-8\right)\left(-x+1\right)
Factor out common term x-8 by using distributive property.
x=8 x=1
To find equation solutions, solve x-8=0 and -x+1=0.
2x-x^{2}+7x-8=0
To find the opposite of x^{2}-7x, find the opposite of each term.
9x-x^{2}-8=0
Combine 2x and 7x to get 9x.
-x^{2}+9x-8=0
All equations of the form ax^{2}+bx+c=0 can be solved using the quadratic formula: \frac{-b±\sqrt{b^{2}-4ac}}{2a}. The quadratic formula gives two solutions, one when ± is addition and one when it is subtraction.
x=\frac{-9±\sqrt{9^{2}-4\left(-1\right)\left(-8\right)}}{2\left(-1\right)}
This equation is in standard form: ax^{2}+bx+c=0. Substitute -1 for a, 9 for b, and -8 for c in the quadratic formula, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.
x=\frac{-9±\sqrt{81-4\left(-1\right)\left(-8\right)}}{2\left(-1\right)}
Square 9.
x=\frac{-9±\sqrt{81+4\left(-8\right)}}{2\left(-1\right)}
Multiply -4 times -1.
x=\frac{-9±\sqrt{81-32}}{2\left(-1\right)}
Multiply 4 times -8.
x=\frac{-9±\sqrt{49}}{2\left(-1\right)}
Add 81 to -32.
x=\frac{-9±7}{2\left(-1\right)}
Take the square root of 49.
x=\frac{-9±7}{-2}
Multiply 2 times -1.
x=-\frac{2}{-2}
Now solve the equation x=\frac{-9±7}{-2} when ± is plus. Add -9 to 7.
x=1
Divide -2 by -2.
x=-\frac{16}{-2}
Now solve the equation x=\frac{-9±7}{-2} when ± is minus. Subtract 7 from -9.
x=8
Divide -16 by -2.
x=1 x=8
The equation is now solved.
2x-x^{2}+7x-8=0
To find the opposite of x^{2}-7x, find the opposite of each term.
9x-x^{2}-8=0
Combine 2x and 7x to get 9x.
9x-x^{2}=8
Add 8 to both sides. Anything plus zero gives itself.
-x^{2}+9x=8
Quadratic equations such as this one can be solved by completing the square. In order to complete the square, the equation must first be in the form x^{2}+bx=c.
\frac{-x^{2}+9x}{-1}=\frac{8}{-1}
Divide both sides by -1.
x^{2}+\frac{9}{-1}x=\frac{8}{-1}
Dividing by -1 undoes the multiplication by -1.
x^{2}-9x=\frac{8}{-1}
Divide 9 by -1.
x^{2}-9x=-8
Divide 8 by -1.
x^{2}-9x+\left(-\frac{9}{2}\right)^{2}=-8+\left(-\frac{9}{2}\right)^{2}
Divide -9, the coefficient of the x term, by 2 to get -\frac{9}{2}. Then add the square of -\frac{9}{2} to both sides of the equation. This step makes the left hand side of the equation a perfect square.
x^{2}-9x+\frac{81}{4}=-8+\frac{81}{4}
Square -\frac{9}{2} by squaring both the numerator and the denominator of the fraction.
x^{2}-9x+\frac{81}{4}=\frac{49}{4}
Add -8 to \frac{81}{4}.
\left(x-\frac{9}{2}\right)^{2}=\frac{49}{4}
Factor x^{2}-9x+\frac{81}{4}. In general, when x^{2}+bx+c is a perfect square, it can always be factored as \left(x+\frac{b}{2}\right)^{2}.
\sqrt{\left(x-\frac{9}{2}\right)^{2}}=\sqrt{\frac{49}{4}}
Take the square root of both sides of the equation.
x-\frac{9}{2}=\frac{7}{2} x-\frac{9}{2}=-\frac{7}{2}
Simplify.
x=8 x=1
Add \frac{9}{2} to both sides of the equation.