Solve 2x-3/2y=5

$$2 x - \frac { 3 } { 2 } y = 5$$

Solve for x

$$x=\frac{3y}{4}+\frac{5}{2}$$

Steps for Solving Linear Equation

Add \frac{3}{2}y to both sides.

$$2x=5+\frac{3}{2}y$$

The equation is in standard form.

$$2x=\frac{3y}{2}+5$$

Divide both sides by 2.

$$\frac{2x}{2}=\frac{\frac{3y}{2}+5}{2}$$

Dividing by 2 undoes the multiplication by 2.

$$x=\frac{\frac{3y}{2}+5}{2}$$

Divide 5+\frac{3y}{2} by 2.

$$x=\frac{3y}{4}+\frac{5}{2}$$

Solve for y

$$y=\frac{4x-10}{3}$$

Steps for Solving Linear Equation

Subtract 2x from both sides.

$$-\frac{3}{2}y=5-2x$$

Divide both sides of the equation by -\frac{3}{2}, which is the same as multiplying both sides by the reciprocal of the fraction.

$$\frac{-\frac{3}{2}y}{-\frac{3}{2}}=\frac{5-2x}{-\frac{3}{2}}$$

Dividing by -\frac{3}{2} undoes the multiplication by -\frac{3}{2}.

$$y=\frac{5-2x}{-\frac{3}{2}}$$

Divide 5-2x by -\frac{3}{2} by multiplying 5-2x by the reciprocal of -\frac{3}{2}.

$$y=\frac{4x-10}{3}$$