Solve 2x(x-8)=(x+1)(2x-3)

$$2 x ( x - 8 ) = ( x + 1 ) ( 2 x - 3 )$$

Solve for x

$$x=\frac{1}{5}=0.2$$

Steps for Solving Linear Equation

Use the distributive property to multiply 2x by x-8.

$$2x^{2}-16x=\left(x+1\right)\left(2x-3\right)$$

Use the distributive property to multiply x+1 by 2x-3 and combine like terms.

$$2x^{2}-16x=2x^{2}-x-3$$

Subtract 2x^{2} from both sides.

$$2x^{2}-16x-2x^{2}=-x-3$$

Combine 2x^{2} and -2x^{2} to get 0.

$$-16x=-x-3$$

Add x to both sides.

$$-16x+x=-3$$

Combine -16x and x to get -15x.

$$-15x=-3$$

Divide both sides by -15.

$$x=\frac{-3}{-15}$$

Reduce the fraction \frac{-3}{-15} to lowest terms by extracting and canceling out -3.

$$x=\frac{1}{5}$$