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x^{2}\left(2x+1\right)-7\left(2x+1\right)
Do the grouping 2x^{3}+x^{2}-14x-7=\left(2x^{3}+x^{2}\right)+\left(-14x-7\right), and factor out x^{2} in the first and -7 in the second group.
\left(2x+1\right)\left(x^{2}-7\right)
Factor out common term 2x+1 by using distributive property. Polynomial x^{2}-7 is not factored since it does not have any rational roots.