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x^{2}\left(2x+7\right)+5\left(2x+7\right)
Do the grouping 2x^{3}+7x^{2}+10x+35=\left(2x^{3}+7x^{2}\right)+\left(10x+35\right), and factor out x^{2} in the first and 5 in the second group.
\left(2x+7\right)\left(x^{2}+5\right)
Factor out common term 2x+7 by using distributive property. Polynomial x^{2}+5 is not factored since it does not have any rational roots.