Solve 2x^3+4x^2-6x

$$2 x ^ { 3 } + 4 x ^ { 2 } - 6 x$$

Factor

$$2x\left(x-1\right)\left(x+3\right)$$

Solution Steps

Factor out 2.

$$2\left(x^{3}+2x^{2}-3x\right)$$

Consider x^{3}+2x^{2}-3x. Factor out x.

$$x\left(x^{2}+2x-3\right)$$

Consider x^{2}+2x-3. Factor the expression by grouping. First, the expression needs to be rewritten as x^{2}+ax+bx-3. To find a and b, set up a system to be solved.

$$a+b=2 ab=1\left(-3\right)=-3$$

Since ab is negative, a and b have the opposite signs. Since a+b is positive, the positive number has greater absolute value than the negative. The only such pair is the system solution.

$$a=-1 b=3$$

Rewrite x^{2}+2x-3 as \left(x^{2}-x\right)+\left(3x-3\right).

$$\left(x^{2}-x\right)+\left(3x-3\right)$$

Factor out x in the first and 3 in the second group.

$$x\left(x-1\right)+3\left(x-1\right)$$

Factor out common term x-1 by using distributive property.

$$\left(x-1\right)\left(x+3\right)$$

Rewrite the complete factored expression.

$$2x\left(x-1\right)\left(x+3\right)$$

Evaluate

$$2x\left(x-1\right)\left(x+3\right)$$