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2\left(x^{3}+12x^{2}+35x\right)
Factor out 2.
x\left(x^{2}+12x+35\right)
Consider x^{3}+12x^{2}+35x. Factor out x.
a+b=12 ab=1\times 35=35
Consider x^{2}+12x+35. Factor the expression by grouping. First, the expression needs to be rewritten as x^{2}+ax+bx+35. To find a and b, set up a system to be solved.
1,35 5,7
Since ab is positive, a and b have the same sign. Since a+b is positive, a and b are both positive. List all such integer pairs that give product 35.
1+35=36 5+7=12
Calculate the sum for each pair.
a=5 b=7
The solution is the pair that gives sum 12.
\left(x^{2}+5x\right)+\left(7x+35\right)
Rewrite x^{2}+12x+35 as \left(x^{2}+5x\right)+\left(7x+35\right).
x\left(x+5\right)+7\left(x+5\right)
Factor out x in the first and 7 in the second group.
\left(x+5\right)\left(x+7\right)
Factor out common term x+5 by using distributive property.
2x\left(x+5\right)\left(x+7\right)
Rewrite the complete factored expression.