Solve for y
y=\frac{2x}{35}-\frac{1}{70x}
x\neq 0
Solve for x
x=\frac{\sqrt{1225y^{2}+4}+35y}{4}
x=\frac{-\sqrt{1225y^{2}+4}+35y}{4}
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2x^{2}-35yx=\frac{1}{2}
Multiply 5 and 7 to get 35.
-35yx=\frac{1}{2}-2x^{2}
Subtract 2x^{2} from both sides.
\left(-35x\right)y=\frac{1}{2}-2x^{2}
The equation is in standard form.
\frac{\left(-35x\right)y}{-35x}=\frac{\frac{1}{2}-2x^{2}}{-35x}
Divide both sides by -35x.
y=\frac{\frac{1}{2}-2x^{2}}{-35x}
Dividing by -35x undoes the multiplication by -35x.
y=\frac{2x}{35}-\frac{1}{70x}
Divide -2x^{2}+\frac{1}{2} by -35x.
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