Solve 2x^2-4x-m=0

$$2 x ^ { 2 } - 4 x - m = 0$$

Solve for m

$$m=2x\left(x-2\right)$$

Steps for Solving Linear Equation

Subtract 2x^{2} from both sides. Anything subtracted from zero gives its negation.

$$-4x-m=-2x^{2}$$

Add 4x to both sides.

$$-m=-2x^{2}+4x$$

The equation is in standard form.

$$-m=4x-2x^{2}$$

Divide both sides by -1.

$$\frac{-m}{-1}=\frac{2x\left(2-x\right)}{-1}$$

Dividing by -1 undoes the multiplication by -1.

$$m=\frac{2x\left(2-x\right)}{-1}$$

Divide 2x\left(2-x\right) by -1.

$$m=-2x\left(2-x\right)$$

Solve for x (complex solution)

$$x=\frac{\sqrt{2m+4}}{2}+1$$

$$x=-\frac{\sqrt{2m+4}}{2}+1$$

Solve for x

$$x=\frac{\sqrt{2m+4}}{2}+1$$

$$x=-\frac{\sqrt{2m+4}}{2}+1\text{, }m\geq -2$$