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2\left(x^{2}-b^{2}\right)-x\left(x^{2}-b^{2}\right)
Do the grouping 2x^{2}-2b^{2}+b^{2}x-x^{3}=\left(2x^{2}-2b^{2}\right)+\left(b^{2}x-x^{3}\right), and factor out 2 in the first and -x in the second group.
\left(x^{2}-b^{2}\right)\left(2-x\right)
Factor out common term x^{2}-b^{2} by using distributive property.
\left(x-b\right)\left(x+b\right)
Consider x^{2}-b^{2}. The difference of squares can be factored using the rule: p^{2}-q^{2}=\left(p-q\right)\left(p+q\right).
\left(-x+2\right)\left(x-b\right)\left(x+b\right)
Rewrite the complete factored expression.