Solve 2x^2=10x

$$2 x ^ { 2 } = 10 x$$

Solve for x

$$x=5$$

$$x=0$$

Steps Using Factoring

Subtract 10x from both sides.

$$2x^{2}-10x=0$$

Factor out x.

$$x\left(2x-10\right)=0$$

To find equation solutions, solve x=0 and 2x-10=0.

$$x=0 x=5$$

Steps Using the Quadratic Formula

Subtract 10x from both sides.

$$2x^{2}-10x=0$$

This equation is in standard form: ax^{2}+bx+c=0. Substitute 2 for a, -10 for b, and 0 for c in the quadratic formula, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.

$$x=\frac{-\left(-10\right)±\sqrt{\left(-10\right)^{2}}}{2\times 2}$$

Take the square root of \left(-10\right)^{2}.

$$x=\frac{-\left(-10\right)±10}{2\times 2}$$

The opposite of -10 is 10.

$$x=\frac{10±10}{2\times 2}$$

Multiply 2 times 2.

$$x=\frac{10±10}{4}$$

Now solve the equation x=\frac{10±10}{4} when ± is plus. Add 10 to 10.

$$x=\frac{20}{4}$$

Divide 20 by 4.

$$x=5$$

Now solve the equation x=\frac{10±10}{4} when ± is minus. Subtract 10 from 10.

$$x=\frac{0}{4}$$

Divide 0 by 4.

$$x=0$$

The equation is now solved.

$$x=5 x=0$$

Steps for Completing the Square

Subtract 10x from both sides.

$$2x^{2}-10x=0$$

Divide both sides by 2.

$$\frac{2x^{2}-10x}{2}=\frac{0}{2}$$

Dividing by 2 undoes the multiplication by 2.

$$x^{2}+\left(-\frac{10}{2}\right)x=\frac{0}{2}$$

Divide -10 by 2.

$$x^{2}-5x=\frac{0}{2}$$

Divide 0 by 2.

$$x^{2}-5x=0$$

Divide -5, the coefficient of the x term, by 2 to get -\frac{5}{2}. Then add the square of -\frac{5}{2} to both sides of the equation. This step makes the left hand side of the equation a perfect square.

$$x^{2}-5x+\left(-\frac{5}{2}\right)^{2}=\left(-\frac{5}{2}\right)^{2}$$

Square -\frac{5}{2} by squaring both the numerator and the denominator of the fraction.

$$x^{2}-5x+\frac{25}{4}=\frac{25}{4}$$

Factor x^{2}-5x+\frac{25}{4}. In general, when x^{2}+bx+c is a perfect square, it can always be factored as \left(x+\frac{b}{2}\right)^{2}.

$$\left(x-\frac{5}{2}\right)^{2}=\frac{25}{4}$$

Take the square root of both sides of the equation.

$$\sqrt{\left(x-\frac{5}{2}\right)^{2}}=\sqrt{\frac{25}{4}}$$

Simplify.

$$x-\frac{5}{2}=\frac{5}{2} x-\frac{5}{2}=-\frac{5}{2}$$

Add \frac{5}{2} to both sides of the equation.

$$x=5 x=0$$