Solve 2x^2+x-a=5

$$2 x ^ { 2 } + x - a = 5$$

Solve for a

$$a=2x^{2}+x-5$$

Steps for Solving Linear Equation

Subtract 2x^{2} from both sides.

$$x-a=5-2x^{2}$$

Subtract x from both sides.

$$-a=5-2x^{2}-x$$

The equation is in standard form.

$$-a=5-x-2x^{2}$$

Divide both sides by -1.

$$\frac{-a}{-1}=\frac{5-x-2x^{2}}{-1}$$

Dividing by -1 undoes the multiplication by -1.

$$a=\frac{5-x-2x^{2}}{-1}$$

Divide 5-2x^{2}-x by -1.

$$a=2x^{2}+x-5$$

Solve for x (complex solution)

$$x=\frac{\sqrt{8a+41}-1}{4}$$

$$x=\frac{-\sqrt{8a+41}-1}{4}$$

Solve for x

$$x=\frac{\sqrt{8a+41}-1}{4}$$

$$x=\frac{-\sqrt{8a+41}-1}{4}\text{, }a\geq -\frac{41}{8}$$