Solve for p (complex solution)
\left\{\begin{matrix}p=-2x-\frac{q}{x}\text{, }&x\neq 0\\p\in \mathrm{C}\text{, }&q=0\text{ and }x=0\end{matrix}\right.
Solve for p
\left\{\begin{matrix}p=-2x-\frac{q}{x}\text{, }&x\neq 0\\p\in \mathrm{R}\text{, }&q=0\text{ and }x=0\end{matrix}\right.
Solve for q
q=-x\left(2x+p\right)
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px+q=-2x^{2}
Subtract 2x^{2} from both sides. Anything subtracted from zero gives its negation.
px=-2x^{2}-q
Subtract q from both sides.
xp=-2x^{2}-q
The equation is in standard form.
\frac{xp}{x}=\frac{-2x^{2}-q}{x}
Divide both sides by x.
p=\frac{-2x^{2}-q}{x}
Dividing by x undoes the multiplication by x.
p=-2x-\frac{q}{x}
Divide -2x^{2}-q by x.
px+q=-2x^{2}
Subtract 2x^{2} from both sides. Anything subtracted from zero gives its negation.
px=-2x^{2}-q
Subtract q from both sides.
xp=-2x^{2}-q
The equation is in standard form.
\frac{xp}{x}=\frac{-2x^{2}-q}{x}
Divide both sides by x.
p=\frac{-2x^{2}-q}{x}
Dividing by x undoes the multiplication by x.
p=-2x-\frac{q}{x}
Divide -2x^{2}-q by x.
px+q=-2x^{2}
Subtract 2x^{2} from both sides. Anything subtracted from zero gives its negation.
q=-2x^{2}-px
Subtract px from both sides.
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