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2x^{2}=18-8
Subtract 8 from both sides.
2x^{2}=10
Subtract 8 from 18 to get 10.
x^{2}=\frac{10}{2}
Divide both sides by 2.
x^{2}=5
Divide 10 by 2 to get 5.
x=\sqrt{5} x=-\sqrt{5}
Take the square root of both sides of the equation.
2x^{2}+8-18=0
Subtract 18 from both sides.
2x^{2}-10=0
Subtract 18 from 8 to get -10.
x=\frac{0±\sqrt{0^{2}-4\times 2\left(-10\right)}}{2\times 2}
This equation is in standard form: ax^{2}+bx+c=0. Substitute 2 for a, 0 for b, and -10 for c in the quadratic formula, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.
x=\frac{0±\sqrt{-4\times 2\left(-10\right)}}{2\times 2}
Square 0.
x=\frac{0±\sqrt{-8\left(-10\right)}}{2\times 2}
Multiply -4 times 2.
x=\frac{0±\sqrt{80}}{2\times 2}
Multiply -8 times -10.
x=\frac{0±4\sqrt{5}}{2\times 2}
Take the square root of 80.
x=\frac{0±4\sqrt{5}}{4}
Multiply 2 times 2.
x=\sqrt{5}
Now solve the equation x=\frac{0±4\sqrt{5}}{4} when ± is plus.
x=-\sqrt{5}
Now solve the equation x=\frac{0±4\sqrt{5}}{4} when ± is minus.
x=\sqrt{5} x=-\sqrt{5}
The equation is now solved.