Solve for y
y=4-x^{2}
Solve for x (complex solution)
x=-\sqrt{4-y}
x=\sqrt{4-y}
Solve for x
x=\sqrt{4-y}
x=-\sqrt{4-y}\text{, }y\leq 4
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2y+8=16-2x^{2}
Subtract 2x^{2} from both sides.
2y=16-2x^{2}-8
Subtract 8 from both sides.
2y=8-2x^{2}
Subtract 8 from 16 to get 8.
\frac{2y}{2}=\frac{8-2x^{2}}{2}
Divide both sides by 2.
y=\frac{8-2x^{2}}{2}
Dividing by 2 undoes the multiplication by 2.
y=4-x^{2}
Divide -2x^{2}+8 by 2.
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