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\frac{6x^{2}+5x-6}{3}
Factor out \frac{1}{3}.
a+b=5 ab=6\left(-6\right)=-36
Consider 6x^{2}+5x-6. Factor the expression by grouping. First, the expression needs to be rewritten as 6x^{2}+ax+bx-6. To find a and b, set up a system to be solved.
-1,36 -2,18 -3,12 -4,9 -6,6
Since ab is negative, a and b have the opposite signs. Since a+b is positive, the positive number has greater absolute value than the negative. List all such integer pairs that give product -36.
-1+36=35 -2+18=16 -3+12=9 -4+9=5 -6+6=0
Calculate the sum for each pair.
a=-4 b=9
The solution is the pair that gives sum 5.
\left(6x^{2}-4x\right)+\left(9x-6\right)
Rewrite 6x^{2}+5x-6 as \left(6x^{2}-4x\right)+\left(9x-6\right).
2x\left(3x-2\right)+3\left(3x-2\right)
Factor out 2x in the first and 3 in the second group.
\left(3x-2\right)\left(2x+3\right)
Factor out common term 3x-2 by using distributive property.
\frac{\left(3x-2\right)\left(2x+3\right)}{3}
Rewrite the complete factored expression.