Solve for x
x=\frac{3-y}{2}
Solve for y
y=3-2x
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2x=3-y
The equation is in standard form.
\frac{2x}{2}=\frac{3-y}{2}
Divide both sides by 2.
x=\frac{3-y}{2}
Dividing by 2 undoes the multiplication by 2.
-y+3=2x
Swap sides so that all variable terms are on the left hand side.
-y=2x-3
Subtract 3 from both sides.
\frac{-y}{-1}=\frac{2x-3}{-1}
Divide both sides by -1.
y=\frac{2x-3}{-1}
Dividing by -1 undoes the multiplication by -1.
y=3-2x
Divide 2x-3 by -1.
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\frac { d } { d x } \frac { ( 3 x ^ { 2 } - 2 ) } { ( x - 5 ) }
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Limits
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