Solve 2x+y+x-1=1+(-4)

$$2 x + y + x - 1 = 1 + ( - 4 )$$

Solve for x

$$x=\frac{-y-2}{3}$$

Steps for Solving Linear Equation

Combine 2x and x to get 3x.

$$3x+y-1=1-4$$

Subtract 4 from 1 to get -3.

$$3x+y-1=-3$$

Subtract y from both sides.

$$3x-1=-3-y$$

Add 1 to both sides.

$$3x=-3-y+1$$

Add -3 and 1 to get -2.

$$3x=-2-y$$

The equation is in standard form.

$$3x=-y-2$$

Divide both sides by 3.

$$\frac{3x}{3}=\frac{-y-2}{3}$$

Dividing by 3 undoes the multiplication by 3.

$$x=\frac{-y-2}{3}$$

Solve for y

$$y=-3x-2$$

Solution Steps

Combine 2x and x to get 3x.

$$3x+y-1=1-4$$

Subtract 4 from 1 to get -3.

$$3x+y-1=-3$$

Subtract 3x from both sides.

$$y-1=-3-3x$$

Add 1 to both sides.

$$y=-3-3x+1$$

Add -3 and 1 to get -2.

$$y=-2-3x$$