Solve for r
\left\{\begin{matrix}r=\frac{b}{x}-2\text{, }&x\neq 0\\r\in \mathrm{R}\text{, }&x=0\text{ and }b=0\end{matrix}\right.
Solve for b
b=x\left(r+2\right)
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rx=b-2x
Subtract 2x from both sides.
xr=b-2x
The equation is in standard form.
\frac{xr}{x}=\frac{b-2x}{x}
Divide both sides by x.
r=\frac{b-2x}{x}
Dividing by x undoes the multiplication by x.
r=\frac{b}{x}-2
Divide b-2x by x.
b=2x+rx
Swap sides so that all variable terms are on the left hand side.
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