Solve 2x+By=C

$$2 x + B y = C$$

Solve for B (complex solution)

$$\left\{\begin{matrix}B=\frac{C-2x}{y}\text{, }&y\neq 0\\B\in \mathrm{C}\text{, }&x=\frac{C}{2}\text{ and }y=0\end{matrix}\right.$$

Steps for Solving Linear Equation

Subtract 2x from both sides.

$$By=C-2x$$

The equation is in standard form.

$$yB=C-2x$$

Divide both sides by y.

$$\frac{yB}{y}=\frac{C-2x}{y}$$

Dividing by y undoes the multiplication by y.

$$B=\frac{C-2x}{y}$$

Solve for B

$$\left\{\begin{matrix}B=\frac{C-2x}{y}\text{, }&y\neq 0\\B\in \mathrm{R}\text{, }&x=\frac{C}{2}\text{ and }y=0\end{matrix}\right.$$

Steps for Solving Linear Equation

Subtract 2x from both sides.

$$By=C-2x$$

The equation is in standard form.

$$yB=C-2x$$

Divide both sides by y.

$$\frac{yB}{y}=\frac{C-2x}{y}$$

Dividing by y undoes the multiplication by y.

$$B=\frac{C-2x}{y}$$

Solve for C

$$C=2x+By$$

Solution Steps

Swap sides so that all variable terms are on the left hand side.

$$C=2x+By$$