Solve for x
x=\frac{100-8y^{2}}{3}
Solve for y (complex solution)
y=-\frac{\sqrt{200-6x}}{4}
y=\frac{\sqrt{200-6x}}{4}
Solve for y
y=\frac{\sqrt{200-6x}}{4}
y=-\frac{\sqrt{200-6x}}{4}\text{, }x\leq \frac{100}{3}
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3x+8y^{2}=100
Combine 2x and x to get 3x.
3x=100-8y^{2}
Subtract 8y^{2} from both sides.
\frac{3x}{3}=\frac{100-8y^{2}}{3}
Divide both sides by 3.
x=\frac{100-8y^{2}}{3}
Dividing by 3 undoes the multiplication by 3.
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