Solve for x
x=\frac{7z-5y^{2}}{2}
Solve for y
y=\frac{\sqrt{35z-10x}}{5}
y=-\frac{\sqrt{35z-10x}}{5}\text{, }x\leq \frac{7z}{2}
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2x=7z-5y^{2}
Subtract 5y^{2} from both sides.
\frac{2x}{2}=\frac{7z-5y^{2}}{2}
Divide both sides by 2.
x=\frac{7z-5y^{2}}{2}
Dividing by 2 undoes the multiplication by 2.
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