Solve for x
x=-\frac{3y}{2}+4
Solve for y
y=\frac{8-2x}{3}
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2x-8=-3y
Subtract 3y from both sides. Anything subtracted from zero gives its negation.
2x=-3y+8
Add 8 to both sides.
2x=8-3y
The equation is in standard form.
\frac{2x}{2}=\frac{8-3y}{2}
Divide both sides by 2.
x=\frac{8-3y}{2}
Dividing by 2 undoes the multiplication by 2.
x=-\frac{3y}{2}+4
Divide -3y+8 by 2.
3y-8=-2x
Subtract 2x from both sides. Anything subtracted from zero gives its negation.
3y=-2x+8
Add 8 to both sides.
3y=8-2x
The equation is in standard form.
\frac{3y}{3}=\frac{8-2x}{3}
Divide both sides by 3.
y=\frac{8-2x}{3}
Dividing by 3 undoes the multiplication by 3.
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Limits
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