Solve for x
x=-\frac{3y}{2}+5
Solve for y
y=\frac{10-2x}{3}
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2x-10=-3y
Subtract 3y from both sides. Anything subtracted from zero gives its negation.
2x=-3y+10
Add 10 to both sides.
2x=10-3y
The equation is in standard form.
\frac{2x}{2}=\frac{10-3y}{2}
Divide both sides by 2.
x=\frac{10-3y}{2}
Dividing by 2 undoes the multiplication by 2.
x=-\frac{3y}{2}+5
Divide -3y+10 by 2.
3y-10=-2x
Subtract 2x from both sides. Anything subtracted from zero gives its negation.
3y=-2x+10
Add 10 to both sides.
3y=10-2x
The equation is in standard form.
\frac{3y}{3}=\frac{10-2x}{3}
Divide both sides by 3.
y=\frac{10-2x}{3}
Dividing by 3 undoes the multiplication by 3.
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Limits
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