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Solve for b
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3b=9c-2x
Subtract 2x from both sides.
\frac{3b}{3}=\frac{9c-2x}{3}
Divide both sides by 3.
b=\frac{9c-2x}{3}
Dividing by 3 undoes the multiplication by 3.
b=-\frac{2x}{3}+3c
Divide 9c-2x by 3.
9c=2x+3b
Swap sides so that all variable terms are on the left hand side.
\frac{9c}{9}=\frac{2x+3b}{9}
Divide both sides by 9.
c=\frac{2x+3b}{9}
Dividing by 9 undoes the multiplication by 9.
c=\frac{b}{3}+\frac{2x}{9}
Divide 2x+3b by 9.