Solve for x
x\leq \frac{7}{3}
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2x+3+x\leq 10
Add x to both sides.
3x+3\leq 10
Combine 2x and x to get 3x.
3x\leq 10-3
Subtract 3 from both sides.
3x\leq 7
Subtract 3 from 10 to get 7.
x\leq \frac{7}{3}
Divide both sides by 3. Since 3 is positive, the inequality direction remains the same.
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