Factor
2\left(w-3\right)\left(w^{2}+3w+9\right)
Evaluate
2\left(w^{3}-27\right)
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2\left(w^{3}-27\right)
Factor out 2.
\left(w-3\right)\left(w^{2}+3w+9\right)
Consider w^{3}-27. Rewrite w^{3}-27 as w^{3}-3^{3}. The difference of cubes can be factored using the rule: a^{3}-b^{3}=\left(a-b\right)\left(a^{2}+ab+b^{2}\right).
2\left(w-3\right)\left(w^{2}+3w+9\right)
Rewrite the complete factored expression. Polynomial w^{2}+3w+9 is not factored since it does not have any rational roots.
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