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w^{2}\left(2w+3\right)-5\left(2w+3\right)
Do the grouping 2w^{3}+3w^{2}-10w-15=\left(2w^{3}+3w^{2}\right)+\left(-10w-15\right), and factor out w^{2} in the first and -5 in the second group.
\left(2w+3\right)\left(w^{2}-5\right)
Factor out common term 2w+3 by using distributive property. Polynomial w^{2}-5 is not factored since it does not have any rational roots.