Solve 2uvdiv2u^2/vdiv2v^2/u

$$2 u v \div \frac { 2 u ^ { 2 } } { v } \div \frac { 2 v ^ { 2 } } { u }$$

Evaluate

$$\frac{1}{2}=0.5$$

Solution Steps

Divide \frac{2uv}{\frac{2u^{2}}{v}} by \frac{2v^{2}}{u} by multiplying \frac{2uv}{\frac{2u^{2}}{v}} by the reciprocal of \frac{2v^{2}}{u}.

$$\frac{2uvu}{\frac{2u^{2}}{v}\times 2v^{2}}$$

Multiply u and u to get u^{2}.

$$\frac{2u^{2}v}{\frac{2u^{2}}{v}\times 2v^{2}}$$

Express \frac{2u^{2}}{v}\times 2 as a single fraction.

$$\frac{2u^{2}v}{\frac{2u^{2}\times 2}{v}v^{2}}$$

Express \frac{2u^{2}\times 2}{v}v^{2} as a single fraction.

$$\frac{2u^{2}v}{\frac{2u^{2}\times 2v^{2}}{v}}$$

Cancel out v in both numerator and denominator.

$$\frac{2u^{2}v}{2\times 2vu^{2}}$$

Cancel out 2vu^{2} in both numerator and denominator.

$$\frac{1}{2}$$

Factor

$$\frac{1}{2} = 0.5$$