Solve 2u^2-2-1/8=0

$$2 u ^ { 2 } - 2 - \frac { 1 } { 8 } = 0$$

Solve for u

$$u = \frac{\sqrt{17}}{4} \approx 1.030776406$$

$$u = -\frac{\sqrt{17}}{4} \approx -1.030776406$$

Steps by Finding Square Root

Subtract \frac{1}{8} from -2 to get -\frac{17}{8}.

$$2u^{2}-\frac{17}{8}=0$$

Add \frac{17}{8} to both sides. Anything plus zero gives itself.

$$2u^{2}=\frac{17}{8}$$

Divide both sides by 2.

$$u^{2}=\frac{\frac{17}{8}}{2}$$

Express \frac{\frac{17}{8}}{2} as a single fraction.

$$u^{2}=\frac{17}{8\times 2}$$

Multiply 8 and 2 to get 16.

$$u^{2}=\frac{17}{16}$$

Take the square root of both sides of the equation.

$$u=\frac{\sqrt{17}}{4} u=-\frac{\sqrt{17}}{4}$$

Steps Using the Quadratic Formula

Subtract \frac{1}{8} from -2 to get -\frac{17}{8}.

$$2u^{2}-\frac{17}{8}=0$$

This equation is in standard form: ax^{2}+bx+c=0. Substitute 2 for a, 0 for b, and -\frac{17}{8} for c in the quadratic formula, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.

$$u=\frac{0±\sqrt{0^{2}-4\times 2\left(-\frac{17}{8}\right)}}{2\times 2}$$

Square 0.

$$u=\frac{0±\sqrt{-4\times 2\left(-\frac{17}{8}\right)}}{2\times 2}$$

Multiply -4 times 2.

$$u=\frac{0±\sqrt{-8\left(-\frac{17}{8}\right)}}{2\times 2}$$

Multiply -8 times -\frac{17}{8}.

$$u=\frac{0±\sqrt{17}}{2\times 2}$$

Multiply 2 times 2.

$$u=\frac{0±\sqrt{17}}{4}$$

Now solve the equation u=\frac{0±\sqrt{17}}{4} when ± is plus.

$$u=\frac{\sqrt{17}}{4}$$

Now solve the equation u=\frac{0±\sqrt{17}}{4} when ± is minus.

$$u=-\frac{\sqrt{17}}{4}$$

The equation is now solved.

$$u=\frac{\sqrt{17}}{4} u=-\frac{\sqrt{17}}{4}$$