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2r^{2}+16r=130
Use the distributive property to multiply 2r by r+8.
2r^{2}+16r-130=0
Subtract 130 from both sides.
r=\frac{-16±\sqrt{16^{2}-4\times 2\left(-130\right)}}{2\times 2}
This equation is in standard form: ax^{2}+bx+c=0. Substitute 2 for a, 16 for b, and -130 for c in the quadratic formula, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.
r=\frac{-16±\sqrt{256-4\times 2\left(-130\right)}}{2\times 2}
Square 16.
r=\frac{-16±\sqrt{256-8\left(-130\right)}}{2\times 2}
Multiply -4 times 2.
r=\frac{-16±\sqrt{256+1040}}{2\times 2}
Multiply -8 times -130.
r=\frac{-16±\sqrt{1296}}{2\times 2}
Add 256 to 1040.
r=\frac{-16±36}{2\times 2}
Take the square root of 1296.
r=\frac{-16±36}{4}
Multiply 2 times 2.
r=\frac{20}{4}
Now solve the equation r=\frac{-16±36}{4} when ± is plus. Add -16 to 36.
r=5
Divide 20 by 4.
r=-\frac{52}{4}
Now solve the equation r=\frac{-16±36}{4} when ± is minus. Subtract 36 from -16.
r=-13
Divide -52 by 4.
r=5 r=-13
The equation is now solved.
2r^{2}+16r=130
Use the distributive property to multiply 2r by r+8.
\frac{2r^{2}+16r}{2}=\frac{130}{2}
Divide both sides by 2.
r^{2}+\frac{16}{2}r=\frac{130}{2}
Dividing by 2 undoes the multiplication by 2.
r^{2}+8r=\frac{130}{2}
Divide 16 by 2.
r^{2}+8r=65
Divide 130 by 2.
r^{2}+8r+4^{2}=65+4^{2}
Divide 8, the coefficient of the x term, by 2 to get 4. Then add the square of 4 to both sides of the equation. This step makes the left hand side of the equation a perfect square.
r^{2}+8r+16=65+16
Square 4.
r^{2}+8r+16=81
Add 65 to 16.
\left(r+4\right)^{2}=81
Factor r^{2}+8r+16. In general, when x^{2}+bx+c is a perfect square, it can always be factored as \left(x+\frac{b}{2}\right)^{2}.
\sqrt{\left(r+4\right)^{2}}=\sqrt{81}
Take the square root of both sides of the equation.
r+4=9 r+4=-9
Simplify.
r=5 r=-13
Subtract 4 from both sides of the equation.