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2n^{2}+4n-2000=0
All equations of the form ax^{2}+bx+c=0 can be solved using the quadratic formula: \frac{-b±\sqrt{b^{2}-4ac}}{2a}. The quadratic formula gives two solutions, one when ± is addition and one when it is subtraction.
n=\frac{-4±\sqrt{4^{2}-4\times 2\left(-2000\right)}}{2\times 2}
This equation is in standard form: ax^{2}+bx+c=0. Substitute 2 for a, 4 for b, and -2000 for c in the quadratic formula, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.
n=\frac{-4±\sqrt{16-4\times 2\left(-2000\right)}}{2\times 2}
Square 4.
n=\frac{-4±\sqrt{16-8\left(-2000\right)}}{2\times 2}
Multiply -4 times 2.
n=\frac{-4±\sqrt{16+16000}}{2\times 2}
Multiply -8 times -2000.
n=\frac{-4±\sqrt{16016}}{2\times 2}
Add 16 to 16000.
n=\frac{-4±4\sqrt{1001}}{2\times 2}
Take the square root of 16016.
n=\frac{-4±4\sqrt{1001}}{4}
Multiply 2 times 2.
n=\frac{4\sqrt{1001}-4}{4}
Now solve the equation n=\frac{-4±4\sqrt{1001}}{4} when ± is plus. Add -4 to 4\sqrt{1001}.
n=\sqrt{1001}-1
Divide -4+4\sqrt{1001} by 4.
n=\frac{-4\sqrt{1001}-4}{4}
Now solve the equation n=\frac{-4±4\sqrt{1001}}{4} when ± is minus. Subtract 4\sqrt{1001} from -4.
n=-\sqrt{1001}-1
Divide -4-4\sqrt{1001} by 4.
n=\sqrt{1001}-1 n=-\sqrt{1001}-1
The equation is now solved.
2n^{2}+4n-2000=0
Quadratic equations such as this one can be solved by completing the square. In order to complete the square, the equation must first be in the form x^{2}+bx=c.
2n^{2}+4n-2000-\left(-2000\right)=-\left(-2000\right)
Add 2000 to both sides of the equation.
2n^{2}+4n=-\left(-2000\right)
Subtracting -2000 from itself leaves 0.
2n^{2}+4n=2000
Subtract -2000 from 0.
\frac{2n^{2}+4n}{2}=\frac{2000}{2}
Divide both sides by 2.
n^{2}+\frac{4}{2}n=\frac{2000}{2}
Dividing by 2 undoes the multiplication by 2.
n^{2}+2n=\frac{2000}{2}
Divide 4 by 2.
n^{2}+2n=1000
Divide 2000 by 2.
n^{2}+2n+1^{2}=1000+1^{2}
Divide 2, the coefficient of the x term, by 2 to get 1. Then add the square of 1 to both sides of the equation. This step makes the left hand side of the equation a perfect square.
n^{2}+2n+1=1000+1
Square 1.
n^{2}+2n+1=1001
Add 1000 to 1.
\left(n+1\right)^{2}=1001
Factor n^{2}+2n+1. In general, when x^{2}+bx+c is a perfect square, it can always be factored as \left(x+\frac{b}{2}\right)^{2}.
\sqrt{\left(n+1\right)^{2}}=\sqrt{1001}
Take the square root of both sides of the equation.
n+1=\sqrt{1001} n+1=-\sqrt{1001}
Simplify.
n=\sqrt{1001}-1 n=-\sqrt{1001}-1
Subtract 1 from both sides of the equation.
x ^ 2 +2x -1000 = 0
Quadratic equations such as this one can be solved by a new direct factoring method that does not require guess work. To use the direct factoring method, the equation must be in the form x^2+Bx+C=0.This is achieved by dividing both sides of the equation by 2
r + s = -2 rs = -1000
Let r and s be the factors for the quadratic equation such that x^2+Bx+C=(x−r)(x−s) where sum of factors (r+s)=−B and the product of factors rs = C
r = -1 - u s = -1 + u
Two numbers r and s sum up to -2 exactly when the average of the two numbers is \frac{1}{2}*-2 = -1. You can also see that the midpoint of r and s corresponds to the axis of symmetry of the parabola represented by the quadratic equation y=x^2+Bx+C. The values of r and s are equidistant from the center by an unknown quantity u. Express r and s with respect to variable u. <div style='padding: 8px'><img src='https://opalmath.azureedge.net/customsolver/quadraticgraph.png' style='width: 100%;max-width: 700px' /></div>
(-1 - u) (-1 + u) = -1000
To solve for unknown quantity u, substitute these in the product equation rs = -1000
1 - u^2 = -1000
Simplify by expanding (a -b) (a + b) = a^2 – b^2
-u^2 = -1000-1 = -1001
Simplify the expression by subtracting 1 on both sides
u^2 = 1001 u = \pm\sqrt{1001} = \pm \sqrt{1001}
Simplify the expression by multiplying -1 on both sides and take the square root to obtain the value of unknown variable u
r =-1 - \sqrt{1001} = -32.639 s = -1 + \sqrt{1001} = 30.639
The factors r and s are the solutions to the quadratic equation. Substitute the value of u to compute the r and s.